- Stays in a straight line
- Moves
- Noise
- Has lights (headlights and antenna)
- Flowers
- Wheels
- Red
- Only goes forward
- Keeps going
- Two seats
Objective:
To find the relationship between the position and time of the buggy.
Trial 1:
Position: units Time:
-30 to -20 .8 seconds
-30 to -10 1.53 seconds
-30 to 0 2.13 seconds
-30 to 10 2.87 seconds
-30 to 20 3.58 seconds
Y=MX+B
Y=14.5x-31.6
We started the buggy at the position of -30 and changed the position of where the buggy stopped. We timed how long it took to get to the position in seconds. is this the plan? should come before the data
Verbal Model: As the time increases, the position increases proportionally.
Math Model: Position = (14.5in/sec)time-31.6inches
Slope: For every one second the time increases the buggy's position increases by 14.5 inches
Y-intercept: -31.6 inches is the initial position of the buggy
Trial 2:
Position: units Time:
-15 to 30 2.4 seconds
-25 to 30 3.51 seconds
-35 to 30 3.9 seconds
-45 to 30 4.7 seconds
-55 to 30 5 seconds
Y=MX+B
Y=-15.03X+23.64
We started the buggy at different positions and kept the stopping position constant at 30. We timed how long it took the buggy to get to the new position.
this analysis does not match the graph??
Verbal Model: As the time increases, the position increases proportionally.
Math Model: Position = (-14.5in/sec)time-31.6inches
Slope: For every one second the time increases the buggy's position increases by 14.5 inches
Y-intercept: -31.6 the initial position of the buggy
Trial 1:
Position: units Time:
-30 to -20 .8 seconds
-30 to -10 1.53 seconds
-30 to 0 2.13 seconds
-30 to 10 2.87 seconds
-30 to 20 3.58 seconds
Y=14.5x-31.6
We started the buggy at the position of -30 and changed the position of where the buggy stopped. We timed how long it took to get to the position in seconds. is this the plan? should come before the data
Verbal Model: As the time increases, the position increases proportionally.
Math Model: Position = (14.5in/sec)time-31.6inches
Slope: For every one second the time increases the buggy's position increases by 14.5 inches
Y-intercept: -31.6 inches is the initial position of the buggy
Trial 2:
Position: units Time:
-15 to 30 2.4 seconds
-25 to 30 3.51 seconds
-35 to 30 3.9 seconds
-45 to 30 4.7 seconds
-55 to 30 5 seconds
Y=MX+B
Y=-15.03X+23.64
We started the buggy at different positions and kept the stopping position constant at 30. We timed how long it took the buggy to get to the new position.
this analysis does not match the graph??
Verbal Model: As the time increases, the position increases proportionally.
Math Model: Position = (-14.5in/sec)time-31.6inches
Slope: For every one second the time increases the buggy's position increases by 14.5 inches
Y-intercept: -31.6 the initial position of the buggy
Conclusion:
Claims and Evidence: The sign of the slope tells whether the buggy moved in a positive or negative direction. Since all buggy's are similar and have a constant speed, the slope should be linear and similar. If the slope is positive than that shows that the buggy moved in a positive direction, but if the slope is negative than the buggy moved in a negative direction. Since the buggys started at different starting points, they all have different y-intercepts.
Errors and Improve/expand: For trial two, my group kept the ending distance constant instead of keeping the starting distance constant. Also human reaction could have messed up the data a little bit because we may not have stopped the time at the right time. how could you fix this?
Journal Statement:
I liked this lab because I thought it was interesting learning the different vocabulary we are supposed to use and how everyone's graph and information was similar even though we tested in different ways. good!
